Using Proof by Induction

Using Proof by Induction

Understanding Proof by Induction

  • Proof by induction is a mathematical technique used primarily to prove a statement about any integer n is true for all values of n greater than or equal to some integer k.

  • The method involves two steps: the base step (base case) and the induction step.

  • During the base step, the statement is proven true for the initial value of n, typically n=1 or n=0.

  • In the induction step, the property is proven to hold true for n = k + 1 assuming it is true for n = k. This is often called the inductive hypothesis.

Role of Proof by Induction

  • The principle of induction is a significant tool in number theory and is frequently used in studying arithmetic and geometric sequences, divisibility, algebra, and more.

  • It’s a powerful method and offers a systematic way of proving otherwise complex mathematical concepts and theorems.

  • It helps us make mathematical statements for an infinite set of cases.

Applying Proof by Induction

  • Define the statement to be proven, and identify the initial integer value, typically denoted as k.

  • Prove the statement is true when n equals to your base case (k). This is sometimes referred to as the basis of induction.

  • Assume the statement is true for n=k. This is your inductive hypothesis.

  • Prove the statement under the assumption that it is true for n=k+1. This is often the hardest step, you may need to manipulate the equations and apply your inductive hypothesis.

  • Your proof is now complete! If you have shown the base case is true, and that true for n=k means it is true for n=k+1, you can state that it is true for all n greater than or equal to k.

Example

  • Prove by induction that 1 + 2 + 3 … + n = n(n + 1) / 2:

    For the base case, when n = 1, the left side is equal to 1 and the right side is also equal to 1.

    For the inductive step, assume the statement is true for n=k (1 + 2 + … + k = k(k + 1) / 2), then you need to show it remains true for n=k+1.

    Adding k+1 to both sides of our inductive hypothesis gives us (1 + 2 + … + k + (k+1) = (k(k + 1) / 2) + k + 1), simplify the right side to get ((k+1)(k+2)/2). This confirms the original statement holds for n=k+1, which completes the proof.

Note: Always remember the process of induction - establish the base case, assume the property for n=k, and show it for n=k+1. Keep practising to get comfortable with the method!